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x^2-432x-3136=0
a = 1; b = -432; c = -3136;
Δ = b2-4ac
Δ = -4322-4·1·(-3136)
Δ = 199168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{199168}=\sqrt{256*778}=\sqrt{256}*\sqrt{778}=16\sqrt{778}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-432)-16\sqrt{778}}{2*1}=\frac{432-16\sqrt{778}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-432)+16\sqrt{778}}{2*1}=\frac{432+16\sqrt{778}}{2} $
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